The theorem states that I = I cm + Mh2, where I cm is the moment of inertia of t

Question

The theorem states that I = I cm + Mh2, where I cm is the moment of inertia of the object relative to an ax axis that passes through the center of mass and is parallel to the axis of interest, M is the total mass of the object, and h is the perpendicular distance between the two axes. Use this theorem and information to determine an expression for moment of inertia of a solid cylinder of radius R relative to an axis that lies on the surface of the cylinder and is perpendicular to the circular ends.

Explanation / Answer

MOI of cylinder about its surface = Icm + mr^2 = mr^2/2 +mr^2 = 3mr^2/2

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