1. The Three Stooges Moving Company slide a 50.0-kg box to the right across a ho
ID: 1975354 • Letter: 1
Question
1. The Three Stooges Moving Company slide a 50.0-kg box to the right across a horizontal floor. Larry pushes the box to the right with a force of 195 N. Moe pulls on the box with a rope that is angled 30? above the horizontal. Curly, who weighs 1100 N, sits on top of the box as it slides. The magnitude of the tension in the rope is 210 N and the coefficient of kinetic friction between the box and the floor is 0.25.(a) What is the acceleration of the box as it slides across the floor?
(b) How long does it take the Stooges to move the box 8.50 m across the floor if it was initially at rest when they began to move it?
(c) At what speed is the box traveling after it has been moved 8.50 m by the Stooges?
Explanation / Answer
Horizontal Component of tension = TCos30 = 210*Cos30 = 181.9 N
Vertical component of tension = TSin30 = 210*Sin30 = 105 N
Normal force = weight of box+Curly -vertical component of tension
= mg + 1100 -105
= 50*9.81 + 1100 - 105
= 1485.5 N
Friction force = *normal force = 0.25*1485.5 = 371.375 N
Net horizontal force on box F = Larry's push + horizontal component of tension - friction
= 195 + 181.9 - 371.375
F = 5.525 N
a) F= ma
5.525 = (50 + 1100/9.81)*a
a = 0.0341 m/s^2
b) s = ut + 1/2*at^2
8.5 = 0 + 1/2*0.0341*t^2
t = 22.3 s
c) v = u + at
= 0 + 0.0341*22.3 = 0.761 m/s
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