A 11 kg hammer strikes a nail at a velocity of 8.9 m/s and comes to rest in a ti

Question

A 11 kg hammer strikes a nail at a velocity of 8.9 m/s and comes to rest in a time interval of 8.0 ms. (a) What is the impulse given to the nail?
kg·m/s
(b) What is the magnitude of the average force acting on the nail?
N A 11 kg hammer strikes a nail at a velocity of 8.9 m/s and comes to rest in a time interval of 8.0 ms. A 11 kg hammer strikes a nail at a velocity of 8.9 m/s and comes to rest in a time interval of 8.0 ms. (a) What is the impulse given to the nail?
kg·m/s
(b) What is the magnitude of the average force acting on the nail?
N (a) What is the impulse given to the nail?
kg·m/s
(b) What is the magnitude of the average force acting on the nail?
N (a) What is the impulse given to the nail?
kg·m/s
(b) What is the magnitude of the average force acting on the nail?
N

Explanation / Answer

impulse is change in momentum...the momentum of the hammer goes from 11kg*8.9m/s to zero, so the change in momentum, or impulse, is 97.9kgm/s impulse = change in momentum = F delta t where F is the force and delta t is the time in which the force acts, so we also know F = impulse/delta t = 97.9kgm/s / 0.008s = 12237.5N

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