A. By what factor is the magnitude of the buoyant force on a completely submerge

Question

A. By what factor is the magnitude of the buoyant force on a completely submerged object multiplied if the object is replaced with one twice as dense?

B. A bargain hunter purchases a "gold" crown at a flea market. After she gets home, she hangs it on a scale and finds its weight to be 7.58 N. She then weighs the crown while its immersed in water, as shown in figure b, and now the scale reads 6.68 N.

What is the density of the crown?
________kg/m3

Is the crown made of pure gold?
yes or no?

The weight of a metal bracelet is measured to be 0.105 N in air and 0.095 N when immersed in water. Find its density.
=________ kg/m3

Explanation / Answer

A)well the buoyancy force on a completely submerged object is dependent only on the volume of the object and the density of the fluid. both of these will not change when changing the density of the object. This means the force will be unchange the factor of magnitude will be 1.

B)So we know the difference the weight when it is not submerged and then fully submerged. This difference in weight can be used to find the volume of the crown.

F=Vg

V=F/(g)=(7.58-6.68)/(1000*9.8)

V=.0000918367 m3

Now we can get the density of the object

Fg=Vg

=Fg/Vg=7.58/(.0000918367*9.8)

=8422.22 kg/m3

Gold has a desnity of 19300 kg/m3 so the crown is not pure gold.

We do a similar process and you get

10500 kg/m3

Hope that helps

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.