Four acrobats of mass 60.5 kg, 68.0 kg, 62.0 kg, and 55.0 kg form a human tower,

Question

Four acrobats of mass 60.5 kg, 68.0 kg, 62.0 kg, and 55.0 kg form a human tower, with each acrobat standing on the shoulders of another acrobat. The 60.5-kg acrobat is at the bottom of the tower.

(a) What is the normal force acting on the 60.5-kg acrobat?
?N

(b) If the area of each of the 60.5-kg acrobat's shoes is 405 cm2, what average pressure (not including atmospheric pressure) does the column of acrobats exert on the floor?
?Pa

(c) Will the pressure be the same if a different acrobat is on the bottom?

Explanation / Answer

a) normal force acting = (60.5+68+62+55)*g = 2405.9 N

b) average pressure = Force/area = 2405.9/(2*405*10^-4) pa = 29702.5 Pa

c) no, it will be different for diferent acrobat, due to different areas of shoes

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