Find the force a 6000 kg person experts on a 70.0 kg person 1.00 meter away (2.8

Question

Find the force a 6000 kg person experts on a 70.0 kg person 1.00 meter away (2.80x 10-7 N) Find the net gravity force on the 500 tonne mass (1 tonne = l000 kg) due to the other two masses. Find (using your data sheet) the force the Sun exerts on the Earth (351 times 1022 N) the force the moon exerts on the Earth (1.99 times 1020 N) Find the force and direction on the upper left mass shown below. Assume the four masses are in deep inter galactic space and the only forces acting on them are the gravity of their neighbours. Each of the masses is 7.50 times 107 kg Find the point between the Earth and the Moon at which the net gravity force on a test mass will be zero. (x = 3.83x107 m from the Moon) The moon's radius can be measured during eclipses when its shadow is cast on the Earth It is found to be about 1740 km. Astronauts on the moon's surface find the free-fall acceleration there to be 1.62 m/s2. Find the mass of the moon based on this data (7.35 times 1022 kg) A planet has twice the mass and five times that radius as the Earth. What will be its gravity field? (0.784N/kg) Find the gravity field 2000 km above the Earth's surface (8380 km from its centre) (5.7 K/kg) On an asteroid, a 1000 kg rock has a weight of 1200 N. The radius of the asteroid is 3500 metres. Find (1.2 N/kg; 2.2 times l017 kg) the gravity field on the asteroid the mass of the asteroid

Explanation / Answer

gravity Field = F/M =Mg/M = g g = G Mearth/d^2 = (6.67 x 10^-11) x (5.98 x 10^24)/8380^2 = 5.67 m/s^2 So gravity Field = 5.67 N/Kg

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