<p>A particle is located at each corner of an imaginary cube. Each edge of the c

Question

<p>A particle is located at each corner of an imaginary cube. Each edge of the cube is <span>0.45</span> m long, and each particle has a mass of <span>0.13</span> kg. What is the moment of inertia of these particles with respect to an axis that lies along one edge of the cube? <br /> <span class="qTextField"> <input id="RN_1609820_8_0_1609836" dir="ltr" name="RN_1609820_8_0_1609836" size="10" type="text" /></span> kg &#183; s²</p>

Explanation / Answer

for some reason your question is not clear.. there are some complex codes written in it i cant read them so. heres the same question with different numbers.. just follow the procedure.. A particle is located at each corner of an imaginary cube. Each edge of the cube is 0.34 m long, and each particle has a mass of 0.31 kg. What is the moment of inertia of these particles with respect to an axis that lies along one edge of the cube? kg · s2 When the axis of rotation is passing through the one of the edges of the cube, there will be 4 particles at a distance of the edge of cube from the axis of rotation and 2 particle are at the surface diagonel length of the cube. The moment of inertia of the particles at the edge distace is I1 = 4ml^2 The moment of inertia of the particles at surface diagonal length of the edge distace is I2 = 2md^2 Where d^2 =2l^2 I2 = 4ml^2 The total moment of inertia of the cube is I =I1+I2 I = 8ml^2 I = 8*0.31*0.34*0.34 I = 0.286 kg m^2 i'm sure now you can do your problem please dont forget to rate my answer :)

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