A dog, with a mass of 9.0 kg, is standing on a flatboat so that he is 24.4 m fro

Question

A dog, with a mass of 9.0 kg, is standing on a flatboat so that he is 24.4 m from the shore. He walks 6.5 m on the boat toward the shore and then stops. The boat has a mass of 40.0 kg. Assuming there is no friction between the boat and the water, how far is the dog from the shore now?

A dog, with a mass of 9.0 kg, is standing on a flatboat so that he is 24.4 m from the shore. He walks 6.5 m on the boat toward the shore and then stops. The boat has a mass of 40.0 kg. Assuming there is no friction between the boat and the water, how far is the dog from the shore now?

Explanation / Answer

m1 * L1  +  m2 * L2 = 0  ( where m1 and m2 are masses of dog and boat repectively  ,  L1  and  L2 are change in positions of dog and boat repectively

=>  9*(  - 6.5 + L) + 40*(L)=0

=> L =  1.194

Distance of the dog from the shore now = 24.4  - 6.5  + L = 19.094m

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