Question Part Points Submissions Used A series circuit contains a 5.0/p-H induct

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A series circuit contains a 5.0/p-H inductor, a 5.0/p - µF capacitor, and a 30.0-O resistor connected to a 120-V (rms) source of variable frequency. Find
1. the resonance frequency f0
1,000 Hz
10 Hz    
100 Hz
10,000 Hz

2. the impedance [O] at f = 60 Hz
1,000 < Z < 10,000
10,000 < Z < 100,000    
0 < Z < 100
100 < Z < 1,000

3. the phase angle f at f = 60 Hz
-p/2 < f < - p/4
0 < f < p/4    
p/4 < f < p/2
-p/4 < f < 0

4. the average power [W] delivered to the circuit at f = 60 Hz
10 < P < 100
100 < P < 1,000    
0 < P < 1
1 < P < 10

5. the instantaneous voltage across R when V(source) is maximum (f = 60 Hz)
0.01 < V < 0.1
0.1 < V < 1.0    
1.0 < V < 10
10 < V < 100

Explanation / Answer

1) resonant frequency =1/(2LC) =100 hz

2)impedance at 60 f =(R2+(Xc-Xl)2 =3033.48

3)phase angle = arctan[(Xc-Xl)/R] = 89.433 degrees

/4<</2

4)Irms=Vrms/Z= 120/3033.48=0.03955 at -89.433 degrees Amps

power =Irms^2*R=0.0469 Watt

0<p<1

5)voltage across R=IRCos(t-)=0.01659

0.01<V<0.1

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