A majorette in a parade is performing some acrobatic twirlings of her baton. Ass
ID: 1969951 • Letter: A
Question
A majorette in a parade is performing some acrobatic twirlings of her baton. Assume that the baton is a uniform rod of mass 0.120 and length 80.0 .Initially, the baton is spinning about a line through its center at angular velocity 3.00. What is its angular momentum?
axis of rotation
A majorette in a parade is performing some acrobatic twirlings of her baton. Assume that the baton is a uniform rod of mass 0.120 and length 80.0 .Initially, the baton is spinning about a line through its center at angular velocity 3.00. What is its angular momentum? axis of rotation ? ?Explanation / Answer
The mass of the rod m = 0.12kg the length of the rod l = 0.8m the angular velocity ?i = 3.0 rad/sec The moment of inertia of rod I = 1/12 mL^2 = (1/12)(0.12)(0.8)^2 = 0.0064 kgm^2 Therefore the angular momentum l = I? = (0.0064)(3.0) = 0.0192 kgm^2/s answer is correct please dont forget to rate my answer :)
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