A boy who has been going up and down snow covered hills on his sled, decides it

Question

A boy who has been going up and down snow covered hills on his sled, decides it is time to go home. As he is walking home, on flat ground, he drags the sled behind him by a rope fastened to the front of the sled. He pulls on the rope with a 2 pound force (8.90 N), which makes an angle of 25 degrees to the level ground. If the sled weighs 10 pounds (44.5), estimate the coefficient of friction between the sled and the snow.

Please Help Me!
I got this wrong on my Midterm and I am trying to do Test Corrections for it. If possible, please provide a picture representation and a Free Body Diagram of all of the forces present. Please explain problem clearly.

Thanks A Ton!!!

Explanation / Answer

Force pulled=8.9 theta=25 Fg=44.5 u? so you need free body diagram Force to the Right with the angle Force of friction the to the left Fg going down Normal going up right? so Sum of Forces=ma N+mgsin25-Fg=0 Set equation = N so it will be N=44.5+44.5sin25 N=63 Sum of forces in X direction = ma mg cos25-uN= ma 44.5cos25-u63= 0 u=

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