A 65-kg man stands on a spring scale in an elevator. Starting from rest, the ele
ID: 1967797 • Letter: A
Question
A 65-kg man stands on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of 1.2 m/s in 0.93 s. The elevator travels with this constant speed for 5.0 s, undergoes a uniform negative acceleration for 1.3 s, and then comes to rest. What does the spring scale register in each of the following time intervals?(a) before the elevator starts to move
N
(b) during the first 0.93 s of the elevator's ascent
N
(c) while the elevator is traveling at constant speed
N
(d) during the elevator's negative acceleration
Explanation / Answer
1)mg = 65*9.8 = 637N 2)a=(1.2-0)/0.93 = 1.29 m/s^2 N = m(g+a) = 65*(9.8+1.29) = 720.85 N 3)mg = 637N 4)a = (0-1.2)/1.3 = -0.923 m/s^2 N = m(g+a) = 65*(9.8-0.923) = 577 N
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