In a popular amusement park ride, a rotating cylinder of radius 2.00 m is set in

Question

In a popular amusement park ride, a rotating cylinder of radius 2.00 m is set in rotation at an angular speed of 7.00 rad/s, as in Figure P7.51. The floor then drops away, leaving the riders suspended against the wall in a vertical position. What minimum coefficient of friction between a rider's clothing and the wall is needed to keep the rider from slipping? (Hint: Recall that the magnitude of the maximum force of static friction is equal to µn, where n is the normal force - in this case, the force causing the centripetal acceleration.)

Explanation / Answer

we have,

friction force = f = mg

N = mg ( N is normal force)

N = m2r

hence,

m2r = mg

2r = g

= (g/2r)

= (9.8/7^2 x 2)

Coefficient of friction = 0.1

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