In a popular amusement park ride, a rotating cylinder of radius 3.00 m is set in

Question

In a popular amusement park ride, a rotating cylinder of radius 3.00 m is set in rotation a speed of 15.0 m/s, as shown in the figure. The floor then drops away, leaving the riders suspended against the wall in a vertical position. Calculate the coefficient of friction needed to keep the riders from slipping. Is this friction kinetic or static? A ball of mass 2.5 kg was thrown against a wall with a speed of 15 m/s at an angle of 25 degree to the horizontal. The ball strikes the wall and rebounds with a speed of 10 m/s at an angle of 20 degree to the horizontal. If the ball was in contact with the wall for 0.125s, how much force did the ball exert on the wall?

Explanation / Answer

given,

velocity = 15 m/s

radius = 3 m

for rider to not to slip

frictional force = weight

k * mv^2 / r = mg

k * v^2 / r = g

k = rg/v^2

k = 3 * 9.8 / 15^2

k = 0.13

this friction is static friction as there is no relative motion between rider and cylinder

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