A pinata of mass M=6.73 kg is attached to a rope of negligible mass that is stru

Question

A pinata of mass M=6.73 kg is attached to a rope of negligible mass that is strung between the tops of two vertical poles. The horizontal distance between the poles is D= 2.98 m and the top of the right pole is a vertical distance h=0.541 m higher than the top of the left pole. The pinata is attached to the rope at a horizontal position halfway between the two poles and at a vertical distance s=1.797 m below the top of the left pole. Find the tension in each part of the rope due to the weight of the pinata.

T1= (N)
T2= (N)

Explanation / Answer

the equilibrium eqn of rope will be given by
T1 cos + mg = T2 cos(90 - )

and

T1 sin = T2 sin (90- )

and tan = 0.784564

= 38.12 degrees

we get T1 = 127.9 N

T2 = 163 N

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