A plane is inclined at an angle of 40 degrees with respect to the horizontal. At

Question

A plane is inclined at an angle of 40 degrees with respect to the horizontal. At a certain distance up the incline, the plane is joined to a horizontal plane. Two blocks, connected by a massless cord plane, are placed on the surfaces as follows. Block #1 with mass 1.50 kg, is placed on the inclined plane, and block #2 with a mass of 2.50 kg, is placed on the horizontal plane. The massless cord is supported by a massless, frictionless, pulley, that is located at the top of the incline at the joint with the inclined and horizontal planes. The contact between the blocks and the plane surfaces is frictionless

* write Newton's equations for block 1 and 2
* calculate the numerical value of the acceleration of each block
* calculate the numerical value of the tension in the cord

Explanation / Answer

let the accelaration of system downward along the incline be 'a' and the tension in the cord be T. m1= 1.5 m2=2.5 for m1, m1*g*sin(40)-T= m1*a......(1) for m2, T=m2*a.........................(2) solve both equation for T and a, m1*g*sin(40)-m2*a=m1*a or,a=2.36m/sec^2 T= 2.5*2.36=5.9 N

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