016 (part 1 of 3) 10.0 points An Alaskan rescue plane traveling 48 m/s drops a p

Question

016 (part 1 of 3) 10.0 points
An Alaskan rescue plane traveling 48 m/s
drops a package of emergency rations from
a height of 165 m to a stranded party of explorers.
The acceleration of gravity is 9.8 m/s2 .
Where does the package strike the ground
relative to the point directly below where it
was released?
Answer in units of m


017 (part 2 of 3)
What is the horizontal component of the ve-
locity just before it hits?
Answer in units of m/s


018 (part 3 of 3)
What is the vertical component of the velocity
just before it hits? (Choose upward as the
positive vertical direction)
Answer in units of m/s

Explanation / Answer

the package travells a verical distance of h = 165m

intial velocity of package in vertical direction = 0m/s

intial velocity of package in horizontal direction = same as aeroplane = 48m/s

acceleration in vertical direction = g = 9.8m/s2

as we know s = u*t+1/2*a*t2 = 0*t+1/2*g*t2

we have 165 = 1/2*9.8*t2 => t = (2*165/9.8) = 5.8s

in 5.8 s horizontal distance travelled = u*t (as there is no acceleration in horizontal direction as we are neglecting air resistances)

=48*5.8 = 278.54m

horizontal component of velocity does not change as there is no horizontal acceleration = 48m/s

vertical component of velocity vy= u-gt = 0-9.8*5.8 = 56.84m/s downward

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