010 points SerPSE9 8.P.022 WI My N The coefficient of friction between the block

Question

010 points SerPSE9 8.P.022 WI My N The coefficient of friction between the block of mass m1-3.00 kg and the surface in the figure below is .-o system starts from rest. What is the speed of the ball of mass m2- 5.00 kg when it has fallen a distan 220. The 1.80 m? ce h m/s Need Help? Read It Watch It 12. -110 points SerPSE9 8 P023.MI FB A 4.80-kg block is set into motion up an inclined plane with an initial speed of v, 7.60 m/s (see figure below). The block comes to rest after traveling d 3.00 m along the plane, which is inclined at an angle of e 30.00 to the horizontal. + My Notes Ask Your Teach

Explanation / Answer

11. on m1: In vertical,

F_net = N1 - m1 g = 0

N1 = m1 g

fk = uk m1 g

in horizontal,

T - fk = m1 a

T - uk m1 g = m1 a ..... (i)

On m2: m2 g - T = m2 a .... (i)

(i) +(ii) => m2 g - uk m1 g = (m1 + m2)a

9.8 ( 5- (0.220 x 3)) = (5 + 3)a

a = 5.32 m/s^2

vf^2 - vi^2 = 2 a d

v^2 - 0^2 = 2(5.32)(1.80)

v = 4.37 m/s .....Ans

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