Evolution PCB4674 HWE practice questions 4 Given initial allele frequencies of A
ID: 196359 • Letter: E
Question
Evolution PCB4674 HWE practice questions 4 Given initial allele frequencies of A: 0.3 and a 0.7, calculate the final allele frequencies and genotype frequencies for a population of 10,000 generation later if selection eliminates 20% of the heterozygotes. individuals one expected genotypor genotype frequency genotype# selection adjusted # allele frequency 0.09 0.42 0.49 900 4200-2096(840) 4900 10000 900 + 0.5(3360) = 2580 2580 , 9160-0.28 Aa 4900 + 0.5(3360) 6580 6580/9160=0.72 9160 5 epeat question 4 assuming that selection eliminates 20% of the individuals with allele A regardless of whether they are homozygous or heterozygous expected genotype frequency genotype# allele frequency expected selection adjusted # 720 + 0.5(3360) = 2400 900-20% (180) = 720 4200-20%(840)=3360 4900 720 720+0.5(3360) 2400 2400/8980 0.09 Aa 0.42 ) / 8980 = 4900 + 0.5(3360)-6580 4900 + 0.5(3360) 6580 O 0.49 0.73 10000 8980 6 Starting with initial allele frequencies of A: 0.5 and a: 0.5, and a population of 9000 viable zygotes, calculate the final allele frequencies if the population receives an influx of 1000 individuals with genotypes AA: 100, Aa: 800, aa: 100. Has the migration caused the population to evolve? expected genotype expected frequency genotype# migration adjusted # allele frequency 0.25 2250 +100 2350 2350 + 0.5(5300) 5000 5000/1000 0.5 0.5 4500 +800=5300 0.25 2250 +100 = 2350 2350 + 0.5(5300) = 5000 5000 / 1000 0.5 9000 10,000 2Explanation / Answer
Hi,
The solutons are solved in the practise sheet.
we need to remember these formulae to solve it.
frequency of AA = p^2
Aa = 2pq
aa = q^2
20% selected means 20% are dead. Rest all parametes are self explanatory. Please go through and get back in comments for any queries.
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