A stop block, s, prevents a crate from sliding down a theta_1 = 27.0^\\circ incl

Question

A stop block, s, prevents a crate from sliding down a theta_1 = 27.0^circ incline. A tensile force F=(F_0 t)~{ m N} acts on the crate parallel to the incline, where F_1 = 275 N/s. If the coefficients of static and kinetic friction between the crate and the incline are mu_s1 = 0.280 and mu_k1 = 0.190, respectively, and the crate has a mass of 43.6 kg, how long will it take until the crate reaches a velocity of 2.77 m/s as it moves up the incline?

Explanation / Answer

at first, after a period of time T1, the friction force will equal to the static friction force. T1=(mg*cos27*ks+mg*sin27)/F0= from now on we have am=F0*t-(mg*cos27*kk+mg*sin27) --> calculate a so we write later the equation of velocity to find Total time

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