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2. In a large population of ruby-throated hummingbirds, it was observed that the

ID: 196029 • Letter: 2

Question

2. In a large population of ruby-throated hummingbirds, it was observed that the frequency of allele H was 0.4 and the frequency of allele h was 0.6. Calculate the expected Hardy-Weinberg equilibrium genotype frequencies. (3 points)

3. In a sample of 100 Hawaiians, it was found that 35, 20, and 45 individuals had blood groups MM, MN, and NN, respectively. Calculate the allele frequencies and the expected Hardy-Weinberg genotypic frequencies. Is this population in Hardy-Weinberg equilibrium? (5 points)

4. In Lop-eared rabbits, about 1 in 1000 has curly hair rather than straight hair; curly hair being due to a recessive gene. What is the proportion of curly alleles in the population? What are the frequencies of homozygous straight hair and of heterozygous straight hair individuals in this population? Assume that the population is in Hardy-Weinberg equilibrium. (3 points)

5. In a population of bark beetles in Minnesota, the following genotypes are observed:

AA (feeds under bark) 0.6

Aa (feeds on top of bark) 0.1

aa (feeds on leaves) 0.3

What are the allele frequencies and expected genotypic frequencies? Explain. (1 point)

Is the population in H-W equilibrium? (NOTE: You do not need to analyze this statistically. Make a judgment based on the proportions). (1 point)

List several biologically valid reasons why the observed population may not be in equilibrium. (3 points)

Explanation / Answer

According to the Chegg guidelines I'll answer the first question when more than one question is posted. Post them separately to get the answers.

3) H is 0.6 that is the genotype HH will have the frequency of 0.6*0.6 = 0.36.

h has the frequency of 0.4 that is hh genotype will have frequency of 0.16.

2Hh that is heterozygous will have 2*0.4*0.6 = 0.48.

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