A 3380.-nF parallel plate capacitor is connected to a 14.4-V battery and charged

Question

A 3380.-nF parallel plate capacitor is connected to a 14.4-V battery and charged.

a) What is the charge Q on the positive plate of the capacitor?

b) What is the electric potential energy stored in the capacitor?

The 3380.-nF capacitor is then disconnected from the 14.4-V battery and used to charge three uncharged capacitors, a 170.-nF capacitor, a 240.-nF capacitor, and a 350.-nF capacitor, connected in series.

c) After charging, what is the potential difference across each of the four capacitors?
[Enter the potential differences across the 3380.-nF capacitor, the170.-nF capacitor, the 240.-nF capacitor, and the 350.-nF capacitor, separated by commas, in units of volts. Example: if you think that the potential difference across the 3380.-nF capacitor is 7 V and across each of the others is 9 V, then you should enter 7,9,9,9].

d) How much of the electrical energy stored in the 3380.-nF capacitor was transferred to the other three capacitors?

Explanation / Answer

A. Charge Q = CV
=3380 nF x 14.4 V
=48.672 C

B. Potential Energy stored = Q2/2C = 0.3504 mJ

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