1. A horizontal force acting on a 2.0 kg object produces an acceleration of 8.0
ID: 1956205 • Letter: 1
Question
1. A horizontal force acting on a 2.0 kg object produces an acceleration of 8.0 m/s^2, find the magnitude of the net force acting on the object.2. A horizontal force of 80.0 N acts on a 4.00 kg mass which is initially at rest. If the force acts for 3.00 sec.
find: a.) the magnitude of the acceleration produced
b.) the distance traveled by the object in 3.00 sec.
3.A 0.050 kg tennis ball approaches a racket at 25 m/s. If it is in contact with the racket's strings for 0.005 sec. then rebounds at 25 m/s, what is the average force the racket exerts on the ball?
Explanation / Answer
1.
F = ma = 2*8 = 16 N
2.
F=ma
Thus a = F/m = 80/4 = 20 m/sec^2
Apply Second equation of Motion
s = ut + 0.5*a*t^2
Here initial velocity,u = 0 m/sec
Thus S = 0.5*at^2 = 0.5*20*3^2 = 90 m
3.
Impulse = Change in Momentum
F*t = m(v-u)
F*0.005 = 0.050*(25 - (-25))
Thus F = 500 N
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