This is 2 problems i did the original problem which asked A 3 kg block is acted

Question

This is 2 problems i did the original problem which asked
A 3 kg block is acted on by a 25-N force that acts 37 degrees below the horizontal. Mk=.2.
It asks for the acceleration when it moves to the right.
So i found that my using EF=ma so (Fcos0 - Fk)/m=a and i found the FN by FN=mg+Fsin0
So i got around 3.7
So For the help i need part b says to do the same problem but the force is not acting 37 degrees above the horizontal i dont understand this i know its simple but what does it mean the equations should be the same right just the angle is different i need help with that. Thanks

Explanation / Answer

It just means that  will be replace by - and no other major changes will happen.....

FN=mg+Fsin will change to FN=mg-Fsin
(Fcos - Fk)/m=a  will remain as it is....

 

Hope the explanation suits you.... :)

 

For more info of part b i have solved it for one guy.... it is http://www.cramster.com/answers-sep-11/physics/frictional-force-problem-invol-3kg-block-acted-25-force-acts-37ordm_1470907.aspx?rec=0

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.