It has been claimed that an insect called the froghopper (Philaenus spumarius) i

Question

It has been claimed that an insect called the froghopper (Philaenus spumarius) is the best jumper in the animal kingdom. This insect can accelerate at 3700 m/s2 over a distance of 1.7 mm as it straightens its specially designed "jumping legs."

(a) Assuming a uniform acceleration, what is the velocity of the insect after it has accelerated through this short distance, and how long did it take to reach that velocity?

velocity: ________ m/s
elapsed time: _______ ms

(b) How high would the insect jump if air resistance could be ignored? Note that the actual height obtained is about 0.7 m, so air resistance is important here.

_______ m

Please help I have a test coming up on this stuff!

Explanation / Answer

a.) You can solve this problem by using: Vf^2 = Vi^2 + 2 * a * d Vf^2 = 0 + 2 * 3700 * 0.0017 Vf = 3.55 m/s For time: Vf = Vi + a * t 3.55 = 0 + 3700 * t t = 0.959 ms b.) Distance if no air resistance: Vf^2 = Vi^2 + 2 * a * d 0 = 3.55^2 + 2 * (-9.8) * d d = 0.642 add 0.0017 meters to d, to get total distance of 0.644 m.

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