Water bottle in a hot car. In the American Southwest, the temperature in a close

Question

Water bottle in a hot car. In the American Southwest, the temperature in a closed car parked in sunlight during the summer can be high enough to burn flesh. Suppose a bottle of water at a refrigerator temperature of 6.11°C is opened, then closed, and then left in a closed car with an internal temperature of 60.7°C. Neglecting the thermal expansion of the water and the bottle, find the pressure (in atm) in the air pocket trapped in the bottle. (The pressure can be enough to push the bottle cap past the threads that are intended to keep the bottle closed.)

Explanation / Answer

initial temparature of the water is Ti=6.11 0C                                                      =279.11 K internal temparature i.e final temparature Tf=60.7 0C                                                                  =333.7 K initial pressure Pi= 1atm from the ideal gas equation PV=nRT here n is the number of moles is constant and R is universal gas constant is also constant in this problem volume also constant therefore Pi/Pf=Ti/Tf final pressure Pf = Pi (Tf/Ti )                           =333.7 /279.11                           = 1.195 atm final pressure Pf = Pi (Tf/Ti )                           =333.7 /279.11                           = 1.195 atm

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.