Water accelerated by a nozzle to 23 m / s strikes the vertical back surface of a

Question

Water accelerated by a nozzle to 23m/s strikes the vertical back surface of a cart moving horizontally at a constant velocity of 7m/s in the flow direction, due to the application of its brakes. The mass flow rate of water through the stationary nozzle is 30kg/s. After the strike, the water stream splatters off in all directions in the plane of the back surface. If the mass of the cart is 405kg and the brakes fail, determine the acceleration of the cart when the water first strikes it. Assume the mass of water that wets the back surface is negligible.

What is the acceleration of the cart?

Explanation / Answer

rate of change of momentum = force

Q' v = F = ma

30 kg/s x 23 m/s = 405 x a >>

a = 1.7037 m/s^2

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