A steel wire is 5 m long and has a cross-sectional area of 0.1 cm^ 2 . Young’s m
ID: 1952291 • Letter: A
Question
A steel wire is 5 m long and has a cross-sectional area of 0.1 cm^
2. Young’s modulus for the material of the wire is 1.7 x 10^12 Pa. The elastic limit is reached at a stress of
3.4 x 10^8 Pa, and the breaking stress is 6.8 x 10^8 Pa. The wire hangs vertically from a
support.
a. What is the maximum load that the wire can support and still be able to return to its original length when the load is removed?
b. What will be the strain in the wire under this load?
c. What will be the extension of the wire under these conditions?
d. What is the maximum load that the wire can support?The weight of the wire may be ignored.
Explanation / Answer
a) load = 3.4 x 10^8 Pa x cross-sectional area of 0.1 cm^2
b) 3.4 x 10^8 = 1.7 x 10^12 x strain
c) calculate strain from b) and solve
strain =l/L , find l
d) max load = 6.8 x 10^8 x cross-sectional area of 0.1 cm^2
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