The pedigree below shows the transmission of albinism in a human family. a. Copy

Question

The pedigree below shows the transmission of albinism in a human family.

a. Copy this pedigree and list the genotypes of all individuals. What is the mode of inheritence?

b. The female on the left in generation I had four children, one of which has albinism. What is the probability that they could have had a total of four children with at least three children having albinism? SHOW WORK

c. What is the probability that male on the far right in generation II has no alleles for albinism (is homozygous for the non-albinism allele)? SHOW WORK

The pedigree below shows the transmission of albinism in a human family. a. Copy this pedigree and list the genotypes of all individuals. b. The female on the left in generation I had four children, one of which has albinism What is the probability that they could have had a total of four children with at least three children having albinism? c. What is the probability that male on the far right in generation II has no alleles for albinism (is homozygous for the non- albinism allele)?

Explanation / Answer

IAnswer

Albinism is a autosomal recessive disease. In its heterogzygous condition it became carrier for the diease.

a)

Gametes. A. a A a A a

Phenotype AA. Aa. Aa. aa   AA. Aa. Aa. aa

b) Aa X. aa

If cross between normal and this albinism then

Phenotype. Aa. Aa. aa. aa Expected probability would be 2: 2 in which 2 is normal and 2 would be albinism

Then if they have 4 children and the three would be albinism, the total probability for albinism is

Probability in one cross * 4

= 2/4*4 = 2 expected probability is 2

C) On the basis of cross the homozygous normal man has a probability of 1/4

Aa Aa Aa

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