Three phase currents are unbalanced and have the following values in per unit Ia

Question

Three phase currents are unbalanced and have the following values in per unit Ia = 2.2 phasor 26.6 degrees A, Ib = 0.6 phasor -156.8 degrees A, Ic = 0.47 phasor 138.7 degrees A. Calculate the symmetrical components Ia1, Ia2, and Ia0.

Solution Applying Equation 13.6 : [Ia1, Ia2, Ia3] = 1/3 [ 1 a a^2] [Ia Ib Ic]

[ 1 a^2 a]

[ 1 1 1 ]

the above values of the phasse currents, these phase currents are made of symmetrical comonents with the positive sequences Ia 1 = 1.0 phasor 15 degrees A, the negative-squence Ia2= 0.75 phasor 30 degrees A, and the zero sequence Ia0 = 0.5 phasor 45 degrees A.

Explanation / Answer

we know 1 1 1 Ia0 Ia1 Ia2=1/3 1 a a^2 1 a^2 a a=cos120+isin120 Solving above equation we get Ia0=0.5(50 degrees) Ia1=1(15) Ia2=.75(30)

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