Three particles, each with a charge of 5.15 ?C and a speed of 355.0 m/s, enter a

Question

Three particles, each with a charge of 5.15 ?C and a speed of 355.0 m/s, enter a uniform magnetic field whose magnitude is 0.635 T.

(A) What is the magnitude of the magnetic force on particle a?

(B) What is the magnitude of the magnetic force on particle b?

(C) What is the magnitude of the magnetic force on particle c?

Three particles, each with a charge of 5.15 ?C and a speed of 355.0 m/s, enter a uniform magnetic field whose magnitude is 0.635 T. What is the magnitude of the magnetic force on particle a? What is the magnitude of the magnetic force on particle b? What is the magnitude of the magnetic force on particle c?

Explanation / Answer

magnetic force on a charged particle is given by F = qvB sin theta

a. Force at a Fa = 5.15uC* 355* 0.635 * sin 30 = 5.8 *10^-4 N

b. Force at b Fb = 5.15uC* 355* 0.635 * sin 0    = 0 N

c. Force at c Fc = 5.15uC* 355* 0.635 * sin 150 = 5.8 *10^-4 N

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