Given the parameters of VDCSOURCE, it acts like a 10V dc power supply in series
ID: 1934121 • Letter: G
Question
Given the parameters of VDCSOURCE, it acts like a 10V dc power supply in series with a switch. The switch closes at 10 seconds and remains closed for the duration of the simulation. Run a 50-second analysis. (a) Find the voltages across the resistors and capacitors at t=0 secondnd 50 seconds.(b) Which of the two capacitor voltages attains the maximum value first and why? (c) Find the circuit current at t=0 seconds and 50 seconds. The hint says (Change the y axis to have maximum value of 100?A). (d) Explain the differences in the amplitude of these currents at zero seconds. (e) Which of the two circuit currents decays at a faster rate and why?
Explanation / Answer
a) at t = 0 sec VR1 = 6.68 V VR2 = 2.32 V Vc1 = 1.1 V Vc2= 5.6V at t = 5 sec VR1 = 0.968 V VR2 = 8.32 V Vc1 = 8.1 V Vc2= 3.6 b) V = Q/C so 10uF will get max value c)at t=0 I = 6.35 mA at t = 5 sec = I = 6.19 mA d) since capacitor will oppose to change in the voltage ; the resistor will have to bear small amount of curent through it e)100k and 10uF will decay faster because of lower time constant
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