A 10mV signal source having an internal resistance of 100kohm is connected to an

Question

A 10mV signal source having an internal resistance of 100kohm is connected to an amplifier for which the input resistance is 10kohm, the open-circuit voltage gain is 1000v/v, and the output resistance is 1kohm. The amplifier is connected in turn a 100ohm load. What overall voltage gain results as measured from the source internal voltage to the load? where did all the gain go? what would the gain be if the source was connected directly to the load? what is the ratio of these two gains? this ratio is a useful measure of the benefit the amplifier brings.

Explanation / Answer

GAIN=[10K/110k]*1000*[100/1100]=8.26V/V GAIN GO IN all the resistance of source and amplifier and current loss occur ratio of gain is 1000/8.26=121.1 this gain is lost from ideal op-amp need to be achieved.

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