during the time channel is open, 4.9 times 10 M into the cell and the same amoun
ID: 1922901 • Letter: D
Question
during the time channel is open, 4.9 times 10 M into the cell and the same amount of CO-3 ions flow out. Given that the length of a typical ion channel is 16 A and that the current produced is 6.2 times 10-12 A, what is the average velocity of the ions in cm/s? Assume that all the ions fit entirely with the channel at one time. Cellular members create voltage potentials by separating the charged ions. A membrane with a 70 mV absolute potential difference has 1 times 104 Na+ ions flowing through it. Assume the potential is constant, what change in electric potential energy is expressed by the Na+ ions? Apply the following questions to both the circuit shown (resistors in series) and the circuit shown in (resistors in parallel) Use Ohm's law with kirchoff's current and voltage laws to derive equations for current i1,i2, and i (through resistor R1, resistor R2, and v. R1 and R2 can be interchanged with an equivalent resistor with resistance R without charging the values of v and i. Shown the derivative of an equation for the equivalent resistance R in terms of R1 and R2.Explanation / Answer
Let's review Ohm's Law and Kirkoff's laws: Ohm's Law: V = IR Loop Law (KVL): V - i(r1 + r2 + ...+ rn) = 0 (series circuit) Nodal Law (KCL): i = i1 + i2 + ... in (parallel circuit) For 5.43a: a. Use the loop law above to start your equation: i1 = 12 = i, because the current across a series circuit remains constant. V - iR1 - iR2 = 0 V = i(R1+R2) This should give you most of the derivations b. R1+R2 = V/i by Ohm's Law, you can substitute for R. For 5.43b a. In a parallel circuit, the voltage remains constant across each resistor, so v1 = v2 = v i = i1 + i2 by Ohm's law, we have: i = v/r1 + v/r2 i = v(1/r1 + 1/r2) b. similar to above. Note: i/v = 1/r by Ohm's law.
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