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The velocity in the outlet pipe from this reservoir is 30ft/s and h= 18ft.; Beca

ID: 1920174 • Letter: T

Question

The velocity in the outlet pipe from this reservoir is 30ft/s and h= 18ft.; Because of the rounded entrance to the pipe, the flow is assumed to be irrotational. Under these conditions, what is the pressure at A?

Evaluate the rotation for r = 0.5, 1, 0, and 1.5. Liquid flows with 1 free surface around a bend. The liquid is inviscid and incompressible, and the flow is steady and irrotational. The velocity varies with the radius across the flow as v = 1/r m/s, where r is in meters. Find the difference in depth of the liquid from the inside to the outside radius. The inside radius of the bend is 1 m and the outside radius is 3 m. The velocity in the outlet pipe from this reservoir is 30 ft/s and h = 18 ft. Because of the rounded entrance to the pipe, the flow is assumed to be irrotational. Under these conditions, what is the pressure at A? The velocity in the outlet pipe from this reservoir is 8 m/s and h = 19 m. Because of the rounded entrance to the pipe, the flow is assumed to be irrotational. Under these conditions, what is the pressure at A?

Explanation / Answer

Height = 18 ft = 5.486 m

Velocity = 30 ft/sec = 9.144 m/sec

Total pressure at point A = density*g*h = 1000*9.81*5.486 = 53817.66 Pa

Now in accordance with equation,

Total pressure = static pressure + dynamic pressure

we have to find static pressure

53817.66 = SP + 0.5*1000*9.144^2

SP = 12011.29 Pascals