The vector A has a magnitude of 6.59 and makes an angle A = 68.7° with the y-axi
ID: 1331580 • Letter: T
Question
The vector A has a magnitude of 6.59 and makes an angle A = 68.7° with the y-axis. The vector B has a magnitude of 9.20 and makes an angle of magnitude B = 53.1° with the x-axis. Note that the vectors are not drawn to scale: redraw them to scale on the axes provided.
2.
Draw the vector A+B. Calculate its components. Enter the x-component first and then the y component.
Draw the vector B-A and calculate components x and y. Calculate the magnitude and direction of B-A. Remember to interpret the inverse tangent function carefully (-90 deg - 90 deg)
Explanation / Answer
A = 6.59sin68.7i + 6.59cos68.7j
A = 6.14i + 2.39j
B = 9.20cos53.1i - 9.20sin53.1j
B = 5.52i - 7.36 j
A + B = 11.66 i - 4.97 j
x-comp = 11.66
y -comp = -4.97
magnitude =sqrt ( 11.66^2 + 4.97^2) =12.68
Direction = tan^-1 (4.97/11.66) =23.09 degree below +ve x-axsi
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B-A = - 3.68i - 9.75j
x- compo = -3.68
y- comp = -9.75
amgnitude = 10.42
direction = tan^-1(9.75/3.68) = 69.32 degrees below -ve x-axis.
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