Two stretched strings are placed next to one another, one with a length of 70.0

Question

Two stretched strings are placed next to one another, one with a length of 70.0 cm and the other with a length of 84.0 cm. The two strings have the same mass per unit length. You pluck the shorter one so that it vibrates at its fundamental frequency. You then adjust the tension in the longer string until it resonates with the first one. To resonate, the two strings must have the same fundamental frequency, so that vibrations on one string can cause the second string to vibrate. (a) What is the ratio of the speed of waves on the shorter string to the speed of waves on the longer string? (b) What is the ratio of the tension in the shorter string to the tension in the longer string?

Explanation / Answer

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