A small spherical object carries a charge of 3.50 nC. (Note: Assume a reference

Question

A small spherical object carries a charge of 3.50 nC. (Note: Assume a reference level of potential V = 0 at r = infinity.) At what distance from the center of the object is the potential equal to the following? 200 V m 100 V m 50.0 V m Is the spacing of the equipotentials proportional to the change in potential? No. The spacing is not proportional to the change in potential. Yes. The spacing is directly proportional to the change in potential. Yes. The spacing is inversely proportional to the change in potential.

Explanation / Answer

V = kq/r k = 8.99x10^9 N.m2/C2 q = charce (1,5nC) r = distance so r=kg/V (8,99x10^9)*(1,5*10^-9)/100= you do the math then just put in 50 and 25 instead of 100 Yes. The spacing is directly proportional to the change in potential.

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