1 )In the population of Pos ock butter the allele A Where lh: , color is p is Y2
ID: 191560 • Letter: 1
Question
1 )In the population of Pos ock butter the allele A Where lh: , color is p is Y2Y2 and the yellow is , ' heteroz -de (Y1Y2) The fitness of Y 1 Y 1, Y 1 Y2 and Y2Y2 is 1.0, 1.0 and 0.3 respectively If the population starts with 500 individuals, after 1000 generations, predict what will happen in the Peacock butterfly population olor of the "eye" on the wing depends of ype represented with Y1Y1 the white color Select one a. There will be same frequency of blue and yellow teye spot Peacock butterflies in the population b. All Peacock butterflies will be with yellow eye spots on the wings c. There will be decline in frequency of Peacock butterflies with yellow 'eye' spots d. There will be no change in the phenotype frequency in the population 2) The population of turtles at the turtle pond is in Hardy-Weinberg equbrium If we have a population of 100 individuals with p- 7 and g-0.3 what is the expected count for the heterozygotes in the population? Select one a 50 C. 42 3) consider the genotypes and phenotypes of the model poputation of beads we used in lab (AA=blue, Aa-green, aa=yellow). If a green and a yellow bead produce offspring, what fraction of their offspring do you expect to have the genotype aa? Select one a 2/3 b. 1/2 C 1/4 d 3/4Explanation / Answer
1) The population is in Hardy-Weinberg equilibrium, so there will be no change in the phenotype frequency in the population. So, option D is the correct answer.
2) The number of heterozygotes will be 2pq.
P is 0.7 and q is 0.3. So, 2pq will be 2*0.7*0.3 = 0.42.
This is 42% of the population. So, as there are 100 individuals then the 42% of the population will be 42 people.
Option C is the correct answer.
3) If Aa and aa mate then there are two possible genotypes. One is Aa and second is aa. So the chance of getting aa is 1/2. So, option B is the correct answer.
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