Learning Goal: To practice Problem-Solving Strategy 11.1 Equilibrium of a Rigid

Question

Learning Goal: To practice Problem-Solving Strategy 11.1 Equilibrium of a Rigid Body. A horizontal uniform bar of mass 2.6 and length 3.0 is hung horizontally on two vertical strings. String 1 is attached to the end of the bar, and string 2 is attached a distance 0.65 from the other end. A monkey of mass 1.3 walks from one end of the bar to the other. Find the tension in string 1 at the moment that the monkey is halfway between the ends of the bar. Part C Find , the magnitude of the force of tension in string 1, at the moment that the monkey is halfway between the ends of the bar. Express your answer in newtons using three significant figures.

Explanation / Answer

Sum of the forces in the y direction, Fy

m1 = mass of monkey

=1.3 kg

m2 = mass of bar

= 2.6 kg

Fy = T1+T2 - (m1+m2)g = 0

r1 = radius arm from where T1 acts to where T2 acts on the bar

= 3 - 0.65

= 2.35 m

r2 =radius arm from where the weight acts to where T2 acts on the bar

= 1.5 - 0.65

= 0.85 m

r3 = radius from where T2 acts to where T2 acts on the bar = 0

M=0=(m1+m2)g*r1-T1*r2-T2*r3

M = 0 = (2.6+1.3) (9.8) (2.35) - T1(0.85) - T2(0)

(0.85)T1 = 89.8

T1 = 105.7 N

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