Learning Goal: To practice Problem-Solving Strategy 15.2 Standing Waves. In lab,
ID: 1511783 • Letter: L
Question
Learning Goal:
To practice Problem-Solving Strategy 15.2 Standing Waves.
In lab, your instructor generates a standing wave using a thin string of length L = 1.35 m fixed at both ends. You are told that the standing wave is produced by the superposition of traveling and reflected waves, where the incident traveling waves propagate in the +x direction with an amplitude A = 3.15 mm and a speed vx = 12.5 m/s . The first antinode of the standing wave is a distance of x = 22.5 cm from the left end of the string, while a light bead is placed a distance of 11.3 cm to the right of the first antinode. What is the maximum transverse speed vy of the bead? Make sure to use consistent distance units in your calculations.
Part A
Considering a general standing wave on a string with both ends fixed, choose the image below that has all the nodes N and antinodes A identified correctly.
Considering a general standing wave on a string with both ends fixed, choose the image below that has all the nodes and antinodes identified correctly.
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These points are correctly identified. However, consider the ends of the string that are fixed and therefore do not move.
Part B
Given that the distance from the left end of the string to the first antinode is 22.5 cm , calculate the wavelength of the standing wave on the string. Remember to convert all measurements into units of meters before performing this calculation.
Express your answer in meters.
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Explanation / Answer
Part A
Fourth image is correct, because nodes occur at y=0 and antinodes occur at y=A or -A
Part B
WAVELENGTH = 4* distance between cosecutive node and antinode
= 4*0.225 m = 0.9 m
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