A diverging lens with a focal length of -22 cm and a converging lens with a foca

Question

A diverging lens with a focal length of -22 cm and a converging lens with a focal length of 19 cm have a common central axis. Their separation is 19 cm. An object of height 3.0 cm is 10 cm in front of the diverging lens, on the common central axis. Where does the lens combination produce the final image of the object (the one produced by the second, converging lens)? a) Where is the image located as measured from the converging lens? b) What is the height (absolute value) of that image? c) Is the object real or virtual? d) Does the image have the same orientation as the object or is it inverted?

Explanation / Answer

si1 = (so1f1)/(so1-f1) = (10* -22)/(10+22) = -6.88 cm so2 = d - si1 = 19 + 6.88 = 25.88 cm si2 = (so2f2)/(so2-f2) = (25.88*19)/(25.88-19) = 71.47 cm

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