A gas expands from I to F in the figure. The energy added to the gas by heat is

Question

A gas expands from I to F in the figure. The energy added to the gas by heat is 470 J when the gas goes from I to F along the diagonal path. What is the change in internal energy of the gas? Answer in units of J. How much energy must be added to the gas by heat for the indirect path IAF to give the same change in internal energy? Answer in units of J.

Explanation / Answer

I-> F W = 3.5 atm* 1.5 L/2 + 0.5 atm * 1.5 L = (3.5/2 + 0.5 ) atm* 1.5 L = 2.25 atm * 1.5 L =2.28E5 Pa * 0.0015 m^3=342 J dU = Q - W = 470-342 = 128 J b) on the path I A F work = (3.5 + 0.5 ) atm*1.5 L =405300 * 0.0015=608 J dU = Q - W Q = dU + W = 128+608= 736 J

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