A 10.5 gram wad of sticky clay is hurled horizontally at a 115 g wooden block in

Question

A 10.5 gram wad of sticky clay is hurled horizontally at a 115 g wooden block initially at rest on a horizontal surface. The clay sticks to the block. After impact, the block slides 7.50 m before coming to rest. If the coefficient of friction between block and surface is 0.650, what was the speed of the clay immediately before impact? ________ m/s

Explanation / Answer

let (u) be the speed of clay before impact> and let the system begins to move with V (joint speed) before the friction bring it to halt after traveling 7.5 m. --------------------------------------… momentum conservation> before = after 0.0105*u + 0 (wooden block at rest) = (0.0105+0.115) V V = [251/21] u ---------------- (1) ------------------------- retarding force = friction = - uk * M g acceleration = a = - uk*g = - 0.65*9.8 = - 6.37 m/s^2 v(final) =0 s = 7.5 m v(final)^2 = V^2 + 2 a s

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