A house painter is standing on a uniform, horizontal platform that is held in eq

Question

A house painter is standing on a uniform, horizontal platform that is held in equilibrium by two cables attached to supports on the roof (as shown in the figure below ). The painter has a mass of 78.6 kg and the mass of the platform is 20.7 kg. The distance from the left end of the platform to where the painter is standing is d = 1.81 m and the total length of the platform is 4.11 m. How large is the force exerted by the left-hand cable on the platform? How large is the force exerted by the right-hand cable? dont understand the solution from chegg...

Explanation / Answer

a) ) How large is the force exerted by the left-hand cable on the platform? in Newtons

b) How large is the force exerted by the right-hand cable? in Newtons

• SIMILAR PLEASE RATEr

a) ) How large is the force exerted by the left-hand cable on the platform? in Newtons

b) How large is the force exerted by the right-hand cable? in Newtons

• SIMILAR PLEASE RATEr

a) ) How large is the force exerted by the left-hand cable on the platform? in Newtons

b) How large is the force exerted by the right-hand cable? in Newtons The weight of the platform will be distributed between the cables evenly.

so 20.2 kg * 9.81(m/s^2) = 198.162 N

so half on each cable or 99.1 newtons on each cable due to the platform

painter's weight = 74 * 9.81 = 725.94

his weight is distributed according to his position.

if d is the distance from the left, the painter's weight on the left cord will be
((4.9-d)/4.9)*725.94

and his weight on the right cord
d/4.9*725.94

sanity check, if he is standing at the left cord, all his weight will be on the left cord, so check that formula for d = 0, we get 4.9-0/4.9*725.94 or the whole 725.94 ..... check

now for the answers

a) weight of platform + weight of painter

99.1 + ((4.9-2)/4.9)725.94 = 99.1 +429.6 = 528.7 N

b)

99.1 + (2/4.9)725.94 = 99.1 + 296.3 = 395.4 N

another sanity check the two cords have to support all of the weight

painter + platform = 725.94 + 198.162 = 924.1

left cord + right cord = 528.7 + 395.4 = 924.1

looks good The weight of the platform will be distributed between the cables evenly.

so 20.2 kg * 9.81(m/s^2) = 198.162 N

so half on each cable or 99.1 newtons on each cable due to the platform

painter's weight = 74 * 9.81 = 725.94

his weight is distributed according to his position.

if d is the distance from the left, the painter's weight on the left cord will be
((4.9-d)/4.9)*725.94

and his weight on the right cord
d/4.9*725.94

sanity check, if he is standing at the left cord, all his weight will be on the left cord, so check that formula for d = 0, we get 4.9-0/4.9*725.94 or the whole 725.94 ..... check

now for the answers

a) weight of platform + weight of painter

99.1 + ((4.9-2)/4.9)725.94 = 99.1 +429.6 = 528.7 N

b)

99.1 + (2/4.9)725.94 = 99.1 + 296.3 = 395.4 N

another sanity check the two cords have to support all of the weight

painter + platform = 725.94 + 198.162 = 924.1

left cord + right cord = 528.7 + 395.4 = 924.1

looks good The weight of the platform will be distributed between the cables evenly.

so 20.2 kg * 9.81(m/s^2) = 198.162 N

so half on each cable or 99.1 newtons on each cable due to the platform

painter's weight = 74 * 9.81 = 725.94

his weight is distributed according to his position.

if d is the distance from the left, the painter's weight on the left cord will be
((4.9-d)/4.9)*725.94

and his weight on the right cord
d/4.9*725.94

sanity check, if he is standing at the left cord, all his weight will be on the left cord, so check that formula for d = 0, we get 4.9-0/4.9*725.94 or the whole 725.94 ..... check

now for the answers

a) weight of platform + weight of painter

99.1 + ((4.9-2)/4.9)725.94 = 99.1 +429.6 = 528.7 N

b)

99.1 + (2/4.9)725.94 = 99.1 + 296.3 = 395.4 N

another sanity check the two cords have to support all of the weight

painter + platform = 725.94 + 198.162 = 924.1

left cord + right cord = 528.7 + 395.4 = 924.1

looks good

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