A object of mass 3.00 kg is subject to a force Fx that varies with position as i

Question

A object of mass 3.00 kg is subject to a force Fx that varies with position as in the figure below.

(a) Find the work done by the force on the object as it moves from x = 0 to x = 2.00 m
J

(b) Find the work done by the force on the object as it moves from x = 5.00 m to x = 8.00 m
J

(c) Find the work done by the force on the object as it moves from x = 10.0 m to x = 15.0 m.
J

(d) If the object has a speed of 0.500 m/s at x = 0, find its speed at x = 5.00 m and its speed at x = 15.0 m.

speed at x = 5.00 m m/s speed at x = 15.0 m m/s A object of mass 3.00 kg is subject to a force Fx that varies with position as in the figure below. (a) Find the work done by the force on the object as it moves from x = 0 to x = 2.00 m J (b) Find the work done by the force on the object as it moves from x = 5.00 m to x = 8.00 m J (c) Find the work done by the force on the object as it moves from x = 10.0 m to x = 15.0 m. J (d) If the object has a speed of 0.500 m/s at x = 0, find its speed at x = 5.00 m and its speed at x = 15.0 m. speed at x = 5.00 m m/s speed at x = 15.0 m m/s

Explanation / Answer

work done is area under the F x graph so a)1/2*2*1=1J b)3*3=9J c)1/2*5*3=7.5J d)work done = change in kinetic energy ==>1/2*(v2^2-0.5^2)3*=1/2*5*3==>V=2.29M/SEC TOTAL AREA=1/2*5*3+5*3+1/2*5*3==>30=1/2*3*(V2^2-0.5^2)==>v=4.5m/sec

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