A bungee jumper undergoes simple harmonic motion with amplitude 4.7m and frequen

Question

A bungee jumper undergoes simple harmonic motion with amplitude 4.7m and frequency 0.135 Hz. Assume the bungee jumper follows the simple harmonic motion equation x = A cos( omega t). Find the jumpers position at 0.25 s. Express your answer to two significant figures and include the appropriate units. Find the jumpers position at 0.50 s. Express your answer to two significant figures and include the appropriate units. Find the jumpers position at 1.0 s. Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

a) x= 4.7*cos(2*pi*0.135*0.25=4.59 m b) 4.7*cos(2*pi*0.135*0.5)=4.28 m c) 4.7*cos(2*pi*0.135*1)=3.108 m

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