A bungee jumper undergoes simple harmonic motion with amplitude 4.3 m and freque

Question

A bungee jumper undergoes simple harmonic motion with amplitude 4.3 m and frequency 0.150 Hz. Assume the bungee jumper follows the simple harmonic motion equation x = A cos (wt).

Part A: Find the jumpers position at 0.25 s.
Express your answer to two significant figures and include the appropriate units.

Part B: Find the jumpers position at 0.50 s.
Express your answer to two significant figures and include the appropriate units.

Part C: Find the jumpers position at 1.0 s.
Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

Given

A = 4.3 m , f = 0.150 Hz

since = 2f = 2 *3.14 *0.15 = 0.942 rad/s

If t = 0.25s

x = 4.3 cos(0.942 *0.25)= 4.29 m

If t = 0.5s

x = 4.3 cos(0.942 *0.5)= 4.29 m

If t = 1s

x = 4.3 cos(0.942 *1)= 4.29 m

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