A 120g ball moving at 0.30m/s in the + x-direction is subject to a 0.20N force i

Question

A 120g ball moving at 0.30m/s in the + x-direction is subject to a 0.20N force in the - y-direction for 1.5s. Find the magnitude of the ball's momentum change. Express your answer to two significant figures and include the appropriate units. Delta p = Find the ball's final speed. Express your answer to two significant figures and include the appropriate units. upsilon = Find the angle between the ball's final velocity and the positive x direction. Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

a)Change in momentum=impulse=Ft=0.2*1.5*(-j)=0.30kgm/s

b)Final velocity=0.3i-0.3/0.12j=0.3i-2.5j

speed=2.52m/s

c)Angle=Tan-1(2.5/0.3)=83 degrees

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