The figure below shows a reversible cycle through which 1.00 mol of a monatomic

Question

The figure below shows a reversible cycle through which 1.00 mol of a monatomic ideal gas is taken. Assume that p = 2po, V = 2Vo, po = 1.47 times 105 Pa, and Vo = 0.0250 m3. Calculate the work done during the cycle. Calculate the energy added during stroke abc. Calculate the efficiency of the cycle. What is the efficiency of an ideal engine operating between the highest and lowest temperatures that occur in the cycle? (Note whether this is greater than or less than the efficiency calculated in (c).)

Explanation / Answer

A) -7.05 Joules/Kelvin is correct, since this is the value found by S = Q/T. Heat exists the hot reservoir thus Q is negative and so is S. B) This answer is ALSO +7.05 J/K. Because this is a REVERSIBLE heat engine, there can be no entropy generation in the engine. All entropy in = all entropy out. C) Zero. Because this is a REVERSIBLE heat engine, there can be no entropy generation in the engine. All entropy in = all entropy out.

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